Problem with subprocess in python

[mfitzsimmons9]

Hi guys, having an issue running a subprocess in python.

if (__name__ == "__main__"):
    D = subprocess.Popen(args=sys.argv[1],
                              stdout=subprocess.PIPE,
                              stdin=subprocess.PIPE)

Whenever I try to execute the script involving this code I get the following error:

Traceback (most recent call last):
File "./attack.py", line 152, in <module>
stdin=subprocess.PIPE)
File "/usr/lib/python2.7/[/FONT]subprocess.py", line 394, in __init__
 errread, errwrite)
File "/usr/lib/python2.7/[FONT=arial]subprocess.py", line 1047, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory

I then altered it to include shell = True, and then I get this issue:

/bin/sh: 1: 5.D: not found

where 5.D is argv[1].

I'm new to Ubuntu so any help would be appreciated

[&KyT$0P#]

Whenever I try to execute the script involving this code

How are you running the script? Please post the full command line.

[mfitzsimmons9]

python ./attack.py 5.D 5.conf

where 5.D and 5.conf are files which exist in the same directory as attack.py

[deadflowr]

Thread moved to Programming Talk

[spjackson]

What happens when you do:

5.D 5.conf

Is 5.D executable? If not then

chmod +x 5.D

Is it on your PATH? If not, either change your PATH or specify the path e.g.

python ./attack.py ./5.D 5.conf

[mfitzsimmons9]

Thanks for the help mate

python ./attack.py ./5.D 5.conf

Solved the problem. I didn't think about the .D file being an executable.