I'm salvaging a computer by starting with nothing installed on a new hard drive to be used for booting. The intention is to install multiple instances of bootable systems. One or more will be Ubuntu. I want each system to be capable of being completely independent (i.e., self contained). In that, I could set the partition it resides in active and it will boot. Also, the failure of any of the systems does not affect the others. However, because there are multiple systems I'd like to be able to select which one I want to run when booting the computer.
To do this I think I need a small partition which is only used to run GRUB2, which will normally be the active partition. Then a completely self contained Ubuntu system is installed in another (i.e., 2nd) partition. Likewise another completely self contained system can be installed in another, 3rd, partition.
It looks to me like I may need to start by installing a complete Ubuntu system (using LiveCD). Let's say into Partition 2. From there I can install grub2 into a different partition by using the grub-install script. Let's say that Partition 1 is the target for grub-install.
Assuming that the above is a valid interpretation of how Ubuntu installation can be done, what is not clear is the minimal requirements for the partition (i.e., size, file system, etc.) that is to be the target of grub-install. The choice of file system likely affects the choice of system to used for emergency repair or update, which means what choice of filesystems is possible?
If this approach is valid what is the best choice for partition size and file system for the grub2 partition (i.e., Partition 1)?
If this is either not valid or a bad approach what is good approach?



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