printf executes before should

[wingnut2626]

#include <stdio.h>



char stringA[256];
char stringB[256];


char *pointerA;
char *pointerB;
char selection;
char selection2;


int main(){


  pointerA = stringA;   
  pointerB = stringB;


  void getFirstString(char *pointer);
  void getSecondString(char *pointer);
  void appendString(char *A, char *B);
  


  getFirstString(pointerA);
  getSecondString(pointerB);
  appendString(pointerA,pointerB);


  return 0;




}






void getFirstString(char *pointer){


  void getValue(char *ptr);
  do{
    printf("What is the first string : ");
    getValue(pointer);
    printf("So your 1string is ");
    puts(pointer);
    printf(" Is this correct?  Y or N : ");
    scanf("%c",&selection);
    }while(selection != 'Y');


}


void getSecondString(char *pointer){
  void getValue(char *ptr);
  do{
    printf("What do you wish to append?");
    getValue(pointer);
    printf("So your 2string is ");
    puts(pointer);
    printf(" Is this correct? Y or N : ");
    scanf("%c",&selection2);
    }while(selection2 != 'Y');


}




void getValue(char *ptr){


  fgets(ptr,120,stdin);




}

For some reason in getSecondString, the printf statement 'So your 2string is' executes before the fgets statement, looking like:

What do you wish to append?So your 2string is

Anyone know why?

[GeneralZod]

For some reason in getSecondString, the printf statement 'So your 2string is' executes before the fgets statement

That's actually not what is happening; add some strategic debugging statements to get a clearer view of what is going on, here

[ofnuts]

By default, when the output is to console, it is line-buffered (in other words output happens when there is a "\n"). So your statement is executed, but the corresponding output is delayed. You have to flush the stream to force output to happen, or you can set the buffering mode for the stream. See http://www.gnu.org/software/libc/man...ling-Buffering