printing certain lines from a file

[sha1sum]

Say I have a text file: story.txt.

Is there a command that allows me to print on the screen only lines 30 to 35 from this file? The only solution I can think of would be this:

$ cat story.txt | head -n 35 | tail -n 5

But that isn't really pretty. Is there a better way?

[Bachstelze]

cat story.txt | sed -n '30,35 p'

[sha1sum]

Thanks!

[sisco311]

Check out BashFAQ 011 (link in my signature) for some examples. In a script I'd use ed:

x=30 y=35
ed -s file << EOF
${x},${y}p
EOF

[sha1sum]

Thank you also. Making scripts is something I'm still learning, but I'll definitely keep that in mind too.

[sha1sum]

Update to my own topic, lol. I did some more studying and I found that you can also do it like this:

cat story.txt | sed '30,35!d'

or even shorter:

sed '30,35!d' story.txt

Basically it tells sed to delete everything, except line 30 to 35.

[vasa1]

Update to my own topic, lol. I did some more studying and I found that you can also do it like this:

cat story.txt | sed '30,35!d'

...

I had done something like that and got this. Ever since then, I've been cautious with cats

[sha1sum]

Did they give you the "Useless Use of Cat Award"? lol. Tell them you gratefully accept and that you've given it an honorable place in /dev/null

Interesting page though. Funny how those kinds of habits sneak in. Thanks for that!

[sha1sum]

New update to my own topic Now I'm studying the use of AWK, and I discovered that in awk you can do it like this:

awk '30<=NR && NR<=35' file.txt

[sha1sum]

Every time I find a new way to do it, I'm going to update this topic. I found that with awk you can also do it like this:

awk 'NR==30,NR==35' file.txt

So many possibilities