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Thread: Learning Matlab

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  1. #1
    Join Date
    Sep 2012
    Beans
    1

    Learning Matlab

    Hi, it's my first time on these forums. I've used Ubuntu before but my question today isn't about Ubuntu, it's about Matlab. I read somewhere that all kinds of languages are discussed on these forums so I decided to try my luck here. My instructor assigns such long projects every week that are very time-consuming but does not really take the time to explain the subject.

    I want to write a program that plots one peicewise function
    f(t) = -Pi*t on −1 ≤ t ≤ 0 and Pi*t on 0 < t ≤ 1 and one Fourier Series F(t) = Pi/2 - 4/Pi Sum[(1/2k+1)*Pi*t*cos(2k-1)] k = 1 to Infinity on −1 ≤ t ≤ 1 using the fplot command. It's only my fourth assignment using Matlab so it's a bit of a jump going from one plot to two or more on the same graph. I wanted to show that I made an attempt at the problem so here is my code so far:


    function Ft = Fourier(t)
    % Ft = Fourier(t)
    % INPUT
    % t: Values between -1 and 1
    %
    % OUTPUT
    % Ft: Fourier approximation
    %
    a=(0:9);
    n=numel(a);
    term(i)=1./(((2.*a(i)-1.^2)).*cos ((2.*a(i)-1)).*pi.*t);
    [x,y]=fplotf(Ft,[-1,1])
    plot(x,y)
    end


    Any help would be appreciated.

  2. #2
    Join Date
    Sep 2006
    Location
    Bruxelles, Belgium
    Beans
    657

    Re: Learning Matlab

    I did not check what your program should do - probably it prints a function in [-1 1] and then, some of its harmonics ...

    Here's the code (it MIGHT help if you check the documentation of fplot carefully )

    Code:
    function run_this_thing % the main function
        t = [-1 1];         % define f,F interval
        fh = @FT;           % function handle
        fplot(fh, t);       % do the plot
    end
    
    function Y = FT(t)       % vectors to plot in
    Y(:,1) = sign(t(:)) * pi;% this is f(t)
    for k = 2: 1: 10         % number of k's ...
        Y(:,k) = pi/2 - 4/pi*sum((1/2*k+1)*pi*t*cos(2*k-1)) ; % this is F(t)              
    end
    
    end

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