Problem with script

[DiegoTc]

Hi
I am trying to make a script that tells me if the file "Hello" appears more than 5 times.

I have the script the following way

var = ls | grep -c Hello 
if [var >5];then
   echo "It appears more than 5"
else
   echo "It appears less than 5 times"
fi

I know that the problem is on the var. But I don't how to assigned the value that grep returns.

[Bachstelze]

var=$(ls | grep -c Hello)

No spaces!

[DiegoTc]

Solve
Thanks

[Vaphell]

[var >5]

that won't work either
here you need everything separated by spaces ( [ is a command, var is first param, > 2nd, 5 third, ] last )
besides var should be used with $ ($var) and > should be replaced with -gt (greater than)
alternatively if you are using bash you can use

if (( var > 5 ))

(()) switches to integer mode but it's not too portable to other shells.

[sisco311]

The output of ls if formated for humans. It will cause bugs in scripts. You should use globs instead:

i=0
for _ in *Hello*
do
   #BASH
   ((i++))
   #POSIX
   #i=$((i+1))
done

#BASH
if (( i>5 ))
#POSIX
#if [ $i -gt 5 ]
then
   :
fi