Using find in a bash script ?

[cyb3r_sn4k3]

I mostly/always use find with -iname and directory as . So I want to make a bash script to do this so how will I get the search string into the bash script?

So here the value of x will change every time I run the script so how will I get the value of x into the script?

~!/bin/bash/ 
find . -iname "*x*"

Sorry if the question is hard to understand

[Dr Small]

#!/bin/bash 
find . -iname "$1"

[nothingspecial]

Putting a / at the end of #! /bin/bash can cause errors.

[cyb3r_sn4k3]

#!/bin/bash/ 
find . -iname "$1"

Can you please explain? The script ?

[DaithiF]

theres not really much to explain, $1, $2, $3 etc. contain the values passed as arguments on the command line when you run a command.

so if you run a script like so:

./yourscript /home/you/somedirectory someotherparameter

then in your script $1 would contain the value /home/you/somedirectory, and $2 would contain someotherparameter

[kevdog]

And $0 would be the name of the script!!

[cyb3r_sn4k3]

Thanks !!

[Dr Small]

Putting a / at the end of #! /bin/bash can cause errors.

Yeah, I didn't mean to do that... :S