sed: Wildcard is Eating Too Much

[Penguin Guy]

I'm trying to remove all comments from a piece of code:

~ $ echo "code # comments # more comments" | sed 's_^\(.*\)#.*$_\1_
code # comments 

As you can see the first wildcard .* is eating as much text as it possibly can, all the way up to the last #. How can I make it eat the bare minimum, only up to the first #?
If this is not possible, then is there some way to process sed backwards so that the last wildcard gets processed first?

Two ways of solving the problem (thanks to MadCow108):

~ $ echo "code # comments # more comments" | sed 's_^\([^#]*\).*$_\1_'
code 

or

~ $ echo "code # comments # more comments" | perl -p -e 's/^(.*?)#.*$/\1/'
code 

[MadCow108]

you could use this:
echo "code # comments # more comments" | sed 's_^\([^#]*\).*$_\1_'

alternativly you could use perl:
echo "code # comments # more comments" | perl -p -e 's/^(.*?)#.*$/\1/'

where .*? means non greedy matching
http://docstore.mik.ua/orelly/perl/cookbook/ch06_16.htm

[Penguin Guy]

you could use this:
echo "code # comments # more comments" | sed 's_^\([^#]*\).*$_\1_'

alternativly you could use perl:
echo "code # comments # more comments" | perl -p -e 's/^(.*?)#.*$/\1/'

where .*? means non greedy matching
http://docstore.mik.ua/orelly/perl/cookbook/ch06_16.htm

Thanks, both solutions work perfectly!