Shell: remove all lines containing specified pattern from all files in a folder

[erotavlas]

Hi,
I would like to remove all lines containing a specified pattern from all files in a folder. I know that the command

grep -v "patternr" ./file > temp && mv temp file

does the first part i.e. removes all lines containing a specified pattern from a specific file. How can I achieve this for all files in a folder?
I tried something like this but it does not work.

grep -Rv "pattern" ./folder > temp && mv temp file

Do I need necessarily iterate over the files of the folder or there is a more simple way?
Thank you

[Vaphell]

what's wrong with loops?

shopt -s globstar
sed -r -i '/pattern/d' ./folder/**/*

globstar for recursiveness, if the files are directly under folder then folder/* would cut it

without globstar

find ./folder -type f -exec sed -r -i /pattern/d +

[erotavlas]

The second solution does not work

find ./folder -type f -exec sed -r -i /pattern/d +
find: missing argument to `-exec'

I also tried to remove + and put ; without difference.

[Vaphell]

a case of brainfart

find ./folder -type f -exec sed -r -i '/pattern/d' {} +

[erotavlas]

Ok thank you

[erotavlas]

I'm sorry, but I have one more question. Now I would like to replace a string with another in each file inside a folder.

find ./folder -type f -exec sed -i 's/Hobbies</span></a> |/Hobbies</span></a>/g' {} +

I make some mistake, or have I to escape some character?

sed: -e expression #1, char 19: unknown option to `s'

Thank you

[Lars Noodén]

find ./folder -type f -exec sed -i 's/Hobbies</span></a> |/Hobbies</span></a>/g' {} +

The slash ( / ) is a the delimiter so you can't use it in any other way without escaping it.

find ./folder -type f -exec sed -i 's/Hobbies<\/span><\/a> |/Hobbies<\/span><\/a>/g' {} +

Alternately, you can use different delimiters like a pound sign ( # ).

find ./folder -type f -exec sed -i 's#Hobbies</span></a> |#Hobbies</span></a>#g' {} +