KMuchane
November 9th, 2008, 07:26 AM
Hi,
I would like to display a photo from an xml document in HTML. The simple xml file below represents the general idea of what I have done:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="car.xsl"?>
<!DOCTYPE car SYSTEM "data1.dtd">
<car>
<make>
VW Beetle
</make>
<dom>
1974
</dom>
<cc>
1199
</cc>
<picture>
pix pic="&pix;"
</picture>
</car>
I read that binary data like the picture can only be referenced in an an attribute. And for some reason the "data1.dtd" is not being read
The simple external dtd looks like:
<?xml version="1.0" ?>
<!ENTITY pix SYSTEM "car.gif">
<!ELEMENT car (make, dom, cc, picture)>
<!ELEMENT make (#PCDATA)>
<!ELEMENT dom (#PCDATA)>
<!ELEMENT cc (#PCDATA)>
Here I am at a loss as to how I would describe the picture element, but my biggest problem is how I would get the car.gif file to be read as a file not as a string. In the present scheme of things Firefox says the entity &pix is not defined, while Opera returns it as a string, with the rest of the elements. When I put the entity pix in an internal dtd the file path name is read as a string :(
Here is the 'car.xsl' file
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/car">
<p><b><xsl:value-of select="."/></b></p>
</xsl:template>
<xsl:template match="/car">
<html>
<title>GARI</title>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
There is something I am missing. I would very much appreciate some guidelines, thanx!
Kinuthia...
I would like to display a photo from an xml document in HTML. The simple xml file below represents the general idea of what I have done:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="car.xsl"?>
<!DOCTYPE car SYSTEM "data1.dtd">
<car>
<make>
VW Beetle
</make>
<dom>
1974
</dom>
<cc>
1199
</cc>
<picture>
pix pic="&pix;"
</picture>
</car>
I read that binary data like the picture can only be referenced in an an attribute. And for some reason the "data1.dtd" is not being read
The simple external dtd looks like:
<?xml version="1.0" ?>
<!ENTITY pix SYSTEM "car.gif">
<!ELEMENT car (make, dom, cc, picture)>
<!ELEMENT make (#PCDATA)>
<!ELEMENT dom (#PCDATA)>
<!ELEMENT cc (#PCDATA)>
Here I am at a loss as to how I would describe the picture element, but my biggest problem is how I would get the car.gif file to be read as a file not as a string. In the present scheme of things Firefox says the entity &pix is not defined, while Opera returns it as a string, with the rest of the elements. When I put the entity pix in an internal dtd the file path name is read as a string :(
Here is the 'car.xsl' file
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/car">
<p><b><xsl:value-of select="."/></b></p>
</xsl:template>
<xsl:template match="/car">
<html>
<title>GARI</title>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
There is something I am missing. I would very much appreciate some guidelines, thanx!
Kinuthia...