[SOLVED] forced float

[chris200x9]

hi I can't figure out what's wrong with this forced float statement


digit = (num/ pow( float base, numDigits - num);

[stroyan]

You didn't say much in your question about your situation.
For example, you didn't mention what language you are coding in. ;-)

I presume you are still coding in C++ as in your previous posts.
And I presume the variables you are using are of type int, resulting in an error like-
call of overloaded ‘pow(int&, int)’ is ambiguous

You need to put the type that you are casting to in parentheses, like

digit = (num/ pow( (float) base, numDigits - num);

[aks44]

I presume you are still coding in C++ as in your previous posts.
[...]
You need to put the type that you are casting to in parentheses, like

digit = (num/ pow( (float) base, numDigits - num);

Funnily enough, you assume that the OP uses C++ but advise to use C casts. :-s

In C++, such a cast is done using static_cast<float>(base). Contrary to unchecked old-style C casts, new-style C++ casts are much safer, better take a good habit as early as possible.

As a side note, doubles are most of the time preferred over floats, there is no performance overhead but the precision is greatly enhanced.

[popch]

hi I can't figure out what's wrong with this forced float statement


digit = (num/ pow( float base, numDigits - num);

The number of left parentheses does not match the number of right ones, to start with.

[chris200x9]

thanks!