C++: cin.getLine -> not found

[Ben Sprinkle]

Guys, I have a program that uses a string, why won't this work?


#include <iostream>

using namespace std;

int main() {
char c[20];
cin.getLine(c, 20, '\n');
}

Shouldn't that work? It says getLine not found in cin.

[lnostdal]

Guys, I have a program that uses a string, why won't this work?


#include <iostream>

using namespace std;

int main() {
char c[20];
cin.getLine(c, 20, '\n');
}

Shouldn't that work? It says getLine not found in cin.




lars@ibmr52:~$ cat blah.cpp
#include <iostream>
#include <string>

using namespace std;

int main()
{
string s;
getline(cin, s);
cout << "you typed: " << s << endl;
return 0;
}
lars@ibmr52:~$ g++ -Wall -g blah.cpp -o blah && ./blah
Hello?
you typed: Hello?

[Ben Sprinkle]

Thanks, do you know how to clear cin? cin.clear(); doesn't do it. I need cin to = "".

[slavik]

cin is an istream type ...

[Ben Sprinkle]

What's that mean?
How do I clear it?

[slavik]

cin is an istream, an istream type is for input streams, which is ways to get input ...

cin is defined to be the standard input.

when you do cin>>var; it will check the type of var and read input into it. since you can't really flush the input buffer, after reading a variable, you can read char by char until EOF is returned ...

[Ben Sprinkle]

How?
Give me an example to clear it please. :)

[po0f]

Goat Spirit,

If you're using C++, why aren't you using std::string? And the following code behaves the way you would expect it to:

#include <iostream>
#include <string>

int main() {
std::string s;
std::cin >> s;

return 0;
}

getline() by default uses '\n' as a delimiter character, but I really don't know if it is taken out of the stream or discarded. I have always used "std::cin >> variable" to get input, which works.

[lnostdal]

Goat Spirit,

If you're using C++, why aren't you using std::string? And the following code behaves the way you would expect it to:

#include <iostream>
#include <string>

int main() {
std::string s;
std::cin >> s;

return 0;
}

getline() by default uses '\n' as a delimiter character, but I really don't know if it is taken out of the stream or discarded. I have always used "std::cin >> variable" to get input, which works.

Try reading in both your first and surname in one go using cin >> variable.

[po0f]

lnostdal,

Goat Spirit was just trying to read in one variable, so I posted an example that did the same. I know that after the space, no more input will be read in, if that's your point.

[Ben Sprinkle]

Thanks all.