View Full Version : Why does "hexdump" reverse bytes?
sha1sum
December 9th, 2013, 08:05 PM
Say we use hexdump in a very simple way:
user@computer:~$ echo "hello" | hexdump
0000000 6568 6c6c 0a6f
0000006
if you look at the hex:
65 = e
68 = h
6c = l
0a = newline
6f = o
So the way it basically prints is like this:
e h l l . o
(where . is newline )
Why does it constantly reverse two bytes?
r-senior
December 9th, 2013, 08:20 PM
It's not reversing them, everything else is:
http://en.wikipedia.org/wiki/Endianness
steeldriver
December 9th, 2013, 08:26 PM
If you want them in character order, I find it easier to use od with the x1 format (hex, single byte)
$ hexdump <<< "hello"
0000000 6568 6c6c 0a6f
0000006
$
$ od -tx1 <<< "hello"
0000000 68 65 6c 6c 6f 0a
0000006
sha1sum
December 13th, 2013, 01:46 PM
It's not reversing them, everything else is:
http://en.wikipedia.org/wiki/Endianness
Interesting. I think I get the concept of endianness.
I still don't really understand why hexdump operates in the way it does. So it reverses two bytes,or you could argue it puts them in the logical order. But why on the two byte level? Why not on the four byte level? Why isn't the entire thing read backwards?
If I were to look at my hard drive, what does a text file with four letters look like? If I use a hex editor to look at a text file, everything is normal, or Big endian, or whatever you call it. While if I examine it with hexdump, it is reversed, or little endian on the two byte level, or someting like that.
The Cog
December 13th, 2013, 02:16 PM
I use hd instead of hexdump. It doesn't answer the question of course, but you may choose to use hd instead, as I did once I found it.
$ echo Hello | hd
00000000 48 65 6c 6c 6f 0a |Hello.|
sha1sum
December 13th, 2013, 03:06 PM
Thanks. That's a nice option too. For my original purpose I fixed it with a pipeline into sed that reverses the two bytes back. Now I´m just curious about this endianness.
Bachstelze
December 15th, 2013, 01:53 PM
I still don't really understand why hexdump operates in the way it does. So it reverses two bytes,or you could argue it puts them in the logical order. But why on the two byte level? Why not on the four byte level? Why isn't the entire thing read backwards?
One has to make a choice. ;) The choice of printing the data in two-byte quantities by default is of course arbitrary, just like the choice of one- or four- or eight-byte quantities would have been.
sha1sum
December 15th, 2013, 03:47 PM
One has to make a choice. ;) The choice of printing the data in two-byte quantities by default is of course arbitrary, just like the choice of one- or four- or eight-byte quantities would have been.
Okay I see. So say if I were to look at my hard drive. What would the order of ones and zeroes look like? Would it be big-endian or little-endian?
Bachstelze
December 15th, 2013, 03:53 PM
I'm not sure it even makes sense to speak of endianness on a hard drive. A hard drive is not linear.
sha1sum
December 15th, 2013, 06:31 PM
hmm, interesting. If it isn't linear, then what is it? Does it contain a two-dimentional matrix of bits?
StephenF
December 16th, 2013, 11:13 AM
A traditional hard drive has typically two or four read heads each scanning a different surface. Older examples may have eight so not having consecutive bits on the same drive platter is the norm. Then there is RAID and LVM which divides up your data in various different ways among drives and partitions. At the filesystem level there is also a thing called file fragmentation that disperses parts of the file among whatever unused blocks are available which brings us onto the topic of block devices.
Drives are block devices which basically means instead of bytes you are grabbing blocks at a time effectively drives are 16384 (or some similar power of 2) bit devices when considering the data bus.
Since the surface, read hardware, and control circuitry are fully integrated the drive manufacturers are free to devise their own encoding schemes and arrangements.
Edit: Back in the 80's those machines had the drive surface details exposed to the operating system.
sha1sum
December 16th, 2013, 12:24 PM
Okay I see. That makes sense. Thanks :D
The Cog
December 16th, 2013, 07:03 PM
I think the byte order of things stored on disk will depend on the file type and the application that writes/reads it.
Many programs will store their data in a specific byte order that is defined by its programmers. I'm pretty sure that sqlite database files fall into this category. These files will be hardware independent and it will be possible to transfer them files meaningfully to other machines which may use different hardware.
I'm guessing, but I think that programs that work by reading/writing memory images will tend to store their 2-byte integers in whichever order the particular processor they are compiled for uses. So that for instance, programs compiled for intel hardware will store the smaller byte first, and programs compiled for ARM hardware will store the larger byte first. This will definitely be true of machine executable program files. Such files will not be sensibly transferable between different hardware architectures.
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