Printing Sequence of Character with Single Space

[1991sudarshan]

How to print a sequence of characters with single space or tabs when the printf command is used in this way ?


#!/bin/bash
for ((x=1;x<=1391;x+=1));
do
echo `printf "%08d" $x`.pdf ;
done
I want the bash to print the output like this


00000001.pdf 00000002.pdf 00000003.pdf .......

[steeldriver]

I don't think you need the 'echo' in there, that will always add the newline - and your format specifier needs to be a string not an integer (you are printing the whole name, not just the $x) - after that, you can just use a literal space as the separator


$ for ((x=1;x<=1391;x+=1)); do printf "%08s " $x.pdf ; doneHowever the built-in sequence syntax would be neater imho:


$ for f in {00000000..00001391}.pdf; do printf "$f "; done

[Vaphell]

echo {0000000..00001391}.pdf
what do you need it for?

[1991sudarshan]

I don't think you need the 'echo' in there, that will always add the newline - and your format specifier needs to be a string not an integer (you are printing the whole name, not just the $x) - after that, you can just use a literal space as the separator


$ for ((x=1;x<=1391;x+=1)); do printf "%08s " $x.pdf ; doneHowever the built-in sequence syntax would be neater imho:


$ for f in {00000000..00001391}.pdf; do printf "$f "; done

Thank you SO Much, that solves the problem.

[1991sudarshan]

echo {0000000..00001391}.pdfwhat do you need it for?

For combing a Chinese Hakka to English Dictionary which I downloaded from the internet. The Dictionary has around 1391 pages. Unfortunately . I got 1391 pdf files. So I wanted to combine it.

Anyways, you idea too worked , Thank you so much.