Simplifying a Chrome channels' versions script

[Intrepid Ibex]

So hi.

I wrote this fairly simple script to check the latest version strings of all the 3 Chrome channels:


#!/bin/bash

cd /tmp
curl -sO http://dl.google.com/linux/chrome/rpm/stable/x86_64/repodata/other.xml.gz
gzip -df other.xml.gz

echo; echo -n "Stable: "
grep '\-stable' other.xml | cut -d " " -f6 | cut -d '"' -f2; echo

echo -n "Beta: "
grep beta other.xml | cut -d " " -f6 | cut -d '"' -f2; echo

echo -n "Unstable: "
grep unstable other.xml | cut -d " " -f6 | cut -d '"' -f2; echo

rm other.xml

Which currently produces:




Stable: 21.0.1180.81

Beta: 22.0.1229.14

Unstable: 23.0.1243.2

My question is: is there a way(s) to simplify this even further (e.g. using awk or a loop for all the three channels or something)?

[Vaphell]

$ awk -F\" '/pkgid/{ sub(".*-","",$4); print $4": "$10 }' other.xml
stable: 21.0.1180.81
beta: 22.0.1229.14
unstable: 23.0.1243.2

[sisco311]

One-liner:



curl -s http://dl.google.com/linux/chrome/rpm/stable/x86_64/repodata/other.xml.gz | gzip -df | awk -F\" '/pkgid/{ sub(".*-","",$4); print $4": "$10 }'

[Intrepid Ibex]

Thanks guys.