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t1497f35
April 21st, 2012, 06:58 PM
Hi,
See text in red box on screenshot, how does one determine which row is greater (i2 > i1)? By its index top down? By the sum of its numbers? In other way?

DaviesX
April 21st, 2012, 07:40 PM
I am not quite sure about it, but I think that suppose to infer to
Intensive row simplified echelon matrix (just translate from other language directly =,=)

echelon matrix
1. all-zero-row should be in the last row
2.the column subscript of the first non-zero element should be increasing as the row subscript is increasing, for example

2 0 2 1
0 5 2 -2
0 0 3 2
0 0 0 0

row simplified matrix
1.it is echelon matrix
2.each column should be all zero except the first non-zero element
for example,

2 0 0 1
0 5 0 -2
0 0 3 2
0 0 0 0

Intensive row simplified echelon matrix
1.it is row simplified matrix
2.every first non-zero element should be 1
For example,
1 0 0 1
0 1 0 -2
0 0 1 2
0 0 0 0

Hope this can help you ^_^

DaviesX
April 21st, 2012, 07:46 PM
I believe that means the specified element of the subscript
if In < In+1 then
Jn < Jn+1

:)

xytron
April 22nd, 2012, 10:47 AM
Indeed you determine which row is greater by its index.

It's referring to the leading entries of a pair of rows, leading entries have to be a 1.

So it says that the leading 1 of any nonzero row has to be in a column with a greater index (to the right) of the leading 1 of the previous row (the row with the lesser index).

t1497f35
April 22nd, 2012, 12:18 PM
Thanks all