Python3: How can I repeat part of a while statement until conditions are met?

[Thorin Oakenshield]

Sorry for the awkward wording of the title. I couldn't think of a better way to word it.

Anyhow, is there a way to repeat a statement until certain conditions are met? Or something like "goto"?

[Tony Flury]

You already know about while statements - so you can simply put one while statement inside another (just make sure you get the indentation right).

A silly example :


a = 0
while a < 10:
print(a)
b = 0
while b < 10:
print(b)
b = b+1
a = a+1
print "finished"

[CoffeeRain]

Are you thinking of an if?


while condition:
if var==var1:
print "var==var1"

[Thorin Oakenshield]

Sort of. I already have an if. I need that to repeat until the user gives specific input.

Tony Flury, that isn't quite what I need.

I have this bit

print("Your current total is ", a + b)
total = a + b
hit = input("hit? y or n")
while total < 21:
if hit == 'y':
c = random.randint(0, 12)
print("your new total is ", a + b + c)
break
elif 21 == total:
print("you win!")
break
elif 21 < total:
print("you bust.")
break
I need the first "if" statement to continue to present itsself until the user inputs "n".

[CoffeeRain]

Sorry if I'm bothering you by trying again, but here's what I interpret you wanting.


var=raw_input('What is your input? ')
while var != var1:
var=raw_input('What is your input? ')

[emiller12345]

You could try something like this, but it's not exactly a 'goto' statment...

import os,sys,random
random.seed(os.urandom(1))

print "stop when x <= 20"
while(1):
x = random.randrange(1, 400, 1)
if x > 20:
sys.stdout.write("wrong,[x="+str(x)+"] ")
continue
#rest of while loop
print
print "Correct! x="+str(x)
exit(0)

[Thorin Oakenshield]

I clarified what i wanted in my previous post.

Also I find no attempt to help annoying :)

[CoffeeRain]

Yes!! I believe this is what you want. I tested this, but I use 2.something, so you may have to change something, but it works for me. :)


import random

a=random.randint(0, 12)
b=random.randint(0, 12)

print("Your current total is ", a + b)
total = a + b
hit = raw_input("Hit? y or n: ")
while hit !='n':
c = random.randint(0, 12)
total=total+c

if 21 == total:
print("you win! You got a " + str(c) + "\n")
break
elif 21 < total:
print("\nyou bust. You got a " + str(c) + "\n")
break

print("your new total is ", total)
hit=raw_input("Hit? y or n: ")

[Thorin Oakenshield]

That is almost the same as my program. Same problem though. Once you input "y" you can't do it again.

[simeon87]

hit = 'bla'
stop = False
while not stop:
while hit != 'n':
hit = input("hit? y or n")

# do other things here
# check if you want to stop permanently here
# stop = True

[Bodsda]

2 minute write up in python 2.x



import random, sys
total = 0

input = ""
while True:
input = raw_input("Hit? Y/N: ").lower()
if input == 'n':
break
else:
total += random.randrange(1, 13)
print "Total: %s" % total

if total > 21:
print "BUST!\nGoodbye"
sys.exit()

dtotal = random.randrange(15, 22)


if total >= dtotal: # quick bodge, assume dealer has between 15 and 21 and cant bust (player wins on draw)
print "Winner!\nYou got: %s\nDealer got: %s" % (total, dtotal)
else:
print "Loser!\nYou got: %s\nDealer got: %s" % (total, dtotal)