[Python] Checking for Compatible Version

[dodle]

I think I've come up with a way to check that some version within a range is being used. I've been testing it and seems to work. But if someone sees an issue would you please point it out. This isn't specifically meant to be used to get the python version, but that is what I am doing in this example.


import sys

min = (2, 5, 0)
max = (2, 7, -1)
try:
version = sys.version_info[:3]
except AttributeError:
sys.exit('Python interpreter version too old')


def MinVersion():
val = 1
x = 0
while (x < 3):
if (val != 1):
return val
if (version[x] >= min[x]):
if (version[x] > min[x]):
val = 2
else:
val = 0
x += 1
return val

def MaxVersion():
val = 1
x = 0
while (x < 3):
if (max[x] < 0):
return 1
if (val != 1):
return val
if (version[x] <= max[x]):
if (version[x] < max[x]):
val = 2
else:
val = 0
x += 1
return val

def MinMaxVersion():
return ((MinVersion() > 0) == (MaxVersion() > 0))

If someone knows of a better way to do this please let me know. I know that sys.hexversion can be used to check for the python version.


>>> print hex(sys.hexversion)
0x20701f0
>>> print sys.hexversion >= 0x20700f0
True

Though I'm not sure why the 'f0' has to be included.

[crdlb]

if not ((2,5) <= (2,7,2) < (3,0)):
throw ...


I normally wouldn't bother checking the python version, but that's how I'd do it.

[dodle]

Thanks, that is helpful. I had tried that before but it wasn't working. I must have done something wrong.


>>> print ((0, 7, 2) > (0, 7, 1))
True