Can't count specific files

[slashwannabe94]

I was wondering how i would count only the files in the current directory and ignore all directories with and without the .. or . prefix. I have got as far as this, but i still end up counting the directories.
ls -a -l | grep -v ^l | wc -l

It's frustrating because i know that i can count all the directories and ignore files, but i can't do it the other way around.
ls -a -I .. -1 --file-type --group-directories-first | grep / | wc -l

Thanks people,
SlashWannabe94

[Bachstelze]

find . -maxdepth 1 -type f | wc -l

[sisco311]

Eh, your command will fail if the directory contains a file with a newline in its name. Check out: http://mywiki.wooledge.org/BashFAQ/004

You can use find to list the files. Read the output of find in a array and print the length of the array.

Didn't tested it, but try something like:


files=()
while IFS= read -d '' -r file
do
files+=("$file")
done< <(find ./ -maxdepth 1 -type f -print0)
echo "${#files[@]}"

[slashwannabe94]

find . -maxdepth 1 -type f | wc -l
Awesome, that's exactly what i was looking for. Thanks so much Bachstelze

SlashWannabe94

[slashwannabe94]

Eh, your command will fail if the directory contains a file with a newline in its name. Check out: http://mywiki.wooledge.org/BashFAQ/004

You can use find to list the files. Read the output of find in a array and print the length of the array.

Didn't tested it, but try something like:


files=()
while IFS= read -d '' -r file
do
files+=("$file")
done< <(find ./ -maxdepth 1 -type f -print0)
echo "${#files[@]}"


That works too :D

Thanks,
SlashWannabe94