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View Full Version : [SOLVED] C - casting as unsigned



marshmallow1304
September 29th, 2010, 04:10 AM
int a = -1;
unsigned b = (unsigned)a;
printf("%d %d\n", a, b);

The output is
-1 -1


Why? I was under the impression that converting from signed to unsigned would, well, drop the sign.

worksofcraft
September 29th, 2010, 04:17 AM
%d interprets the parameter as signed decimal.
If you want unsigned format, then use %u

Note: functions like printf that have variable number of parameters do not recognize the type of their parameters and it is up to the programmer to interpret correctly. If you were writing in C++, then the output stream does understand about type:


// g++ unsigned.cc; ./a.out
#include <iostream>
using namespace std;

int main() {
unsigned U = (unsigned) -1;
signed D = -1;

cout << "unsigned:"<< U << " signed:" << D << endl;
}

marshmallow1304
September 29th, 2010, 04:54 AM
Thank you. That really cleared it up for me.