random pieces of number

[learnbash]

Hello folks,

i have number for example 10 and i want to divide into 4 random pieces that may be (6+2+1+1). How can i do this via script i have random number 234951 and i want to divide into 31 pieces. http://fedora.unix.com/images/misc/progress.gif

[Bachstelze]

Sounds like homework, but it is very vague. What exactly does "random" mean here?

[learnbash]

Sounds like homework, but it is very vague. What exactly does "random" mean here?

Dear sir, as earlier i say 10 we can divide it [6+2+1+1] or [5+2+1+2] or any combination so it could be any random number that makes 10 after breaking into 4 pieces. Same need to do for this number 234951.

[dwhitney67]

learnbash - Why do you need this script?

Learning how to develop software is one thing; asking for a solution to a specific problem seems to imply that you are asking for someone on this forum to do your school work... and that is against the forum policies.

[learnbash]

learnbash - Why do you need this script?

Learning how to develop software is one thing; asking for a solution to a specific problem seems to imply that you are asking for someone on this forum to do your school work... and that is against the forum policies.

dear i am asking for idea, can you help.

[dwhitney67]

dear i am asking for idea, can you help.

No, other than to suggest that you attempt to solve the problem on your own. If during the course of your endeavor you encounter any problems, then please ask again for help. But you better be prepared to show your work.

[Bachstelze]

dear sir, as earlier i say 10 we can divide it [6+2+1+1] or [5+2+1+2] or any combination so it could be any random number that makes 10 after breaking into 4 pieces. Same need to do for this number 234951.

1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+ 1+1+1+1+1+234921

[learnbash]

1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+ 1+1+1+1+1+234921


Hahaha, its not shell script, may be you suggest some logic so i can proceed.

[Bachstelze]

Hahaha, its not shell script, may be you suggest some logic so i can proceed.

Find the maximum value for the first number, choose one value between 1 and that maximum value, repeat for all other numbers.

[learnbash]

Find the maximum value for the first number, choose one value between 1 and that maximum value, repeat for all other numbers.

bc 1.06.95
Copyright 1991-1994, 1997, 1998, 2000, 2004, 2006 Free Software Foundation, Inc.
This is free software with ABSOLUTELY NO WARRANTY.
For details type `warranty'.
234951/31
7579

Dear sir it give 7579, so i need to fill 7579 in all remaining 30 field, is it possible i can get random values other than this 7579 30 times to accomplish 234951

[Bachstelze]

I don't think you can generate random numbers directly in Bash. You can use Python:


python -c "import random; print random.randint(1, n)"

will give you a random number between 1 and n (inclusive).

[DanielWaterworth]

It really depends on what you mean by random. Different algorithms will give different distributions and without knowing what you are using it for it is difficult to say of an approach "This will give the best results".

Although the algorithm outlined by varies people above would be the simplest to implement, that of recursively choosing an integer between 1 and the remaining space left. It is a skewed distribution, ie, the first numbers are bigger in general.

Another approach is to generate a number between 1 and the size. This is the amount of numbers you will generate. Set all of the numbers to one, then randomly increment them until the sum is equal to size. This will generate a distribution that is not skewed.