Bash script to tell you how many days until ubuntu X is released

[alex_o]

i have made a small bash script which assumes that ubuntu is released on the last day of April and October, it then works out the date and finds the difference and tells you if it will be LTS!!!

#!/bin/bash
days(){
[ "$#" == "2" ] && date -d "$1/01/$2 +1month -1day" +%d
[ "$#" == "1" ] && days $1 `date +%Y`
[ "$#" == "0" ] && days `date +%m%Y`
}
month(){
total=0
month=`date +%m`
while [ $month -le $1 ];do
total=$((`days $month` + $total))
month=$(($month+1))
done
total=$(($total - `date +%d`))
echo $total
}
mnth=`date +%m`
LTS=0
if [ $mnth -ge 05 ];then
LTS=0
else
LTS=1
fi
if [ $mnth -ge 11 ];then
LTS=1
fi
if [ $LTS = 1 ];then
if [ $mnth -lt 11 ];then
echo "ubuntu `date +%y`.04LTS available in `month 4` days"
else
echo "ubuntu `date +%y`.04LTS available in $((`month 12`+`month 4`)) days"
fi
else
echo "ubuntu `date +%y`.10 available in `month 10` days"
fi

* function: days is not my code, i copied and pasted it :lolflag:

~enjoy~) :P