[ Ruby ] for loop and break - void value expression ( error ).

[HellBoz]

#!/usr/bin/env ruby

def revnum(num)
return num.to_s().reverse.to_i()
end

for num in (11..10000)
sum = num + revnum(num)
if (sum == revnum(sum))
puts "#{num} is a palindrome ( 1 iteration, result: #{sum} )."
elsif
for iteration in (2..30)
sum = sum + revnum(sum)
if (sum == revnum(sum))
puts "#{num} is a palindrome ( #{iteration} iterations, result: #{sum} )."
break
elsif
if (iteration == 30)
puts "#{num} is a Lychrel number ( #{iteration} iterations, No palindrome could be found )."
break
end
end
end
end
endBasically, once I add the second break statement ( elsif if statement ), the whole application crashes with the following error.


main.rb:23: void value expression
main.rb:24: void value expressionWhat I'm missing here ?

[stylishpants]

The problem is you're starting an if statement and not finishing it.




elsif
if (iteration == 30)
puts "#{num} is a Lychrel number ( #{iteration} iterations, No palindrome could be found )."
break
end
end


main.rb:23: void value expression
main.rb:24: void value expressionWhat I'm missing here ?

You are using an elsif like it is an else. It needs a condition.


Change the "elsif" to an "else" and it will work.
Or, more readably, move this condition: (iteration == 30) to be after the elsif, and then get rid of the unnecessary if/end.

[HellBoz]

Thank you - works like a charm now. Just one thing - if I remove break, those errors doesn't come up at all and everything works as expected, even without the elsif conditional statement :-s