How to make a script that does...

[dwally89]

Hi,

Sorry about the vague title, couldn't think of a more specific one...

How can I write a script that searches through a given folder, and all its subfolders, and reports all files and folders that contain the characters:
* . " / \ [ ] : ; | = ,

Thanks

[Rany Albeg]

Hi ,

Just run a loop like 'for i in $(find <dir>)'
and check equality for each i .

[dwally89]

Sorry, I'm a bit new to all this, please could you be a bit more specific?

[Barriehie]

I'm new to awk so I'll have to work on it a bit but:



#!/bin/bash
ls -lR somedir > ./somefilename
gawk somegawkfile.awk -f somefilename > ./outputfilelist


That should work but I'll have to get back with the somegawkfile.awk part!

Barrie

Edit: After some searching your list can be narrowed a bit! Click here! (http://ubuntuforums.org/showthread.php?t=688615)

[jimi_hendrix]

i am no find pro, but i bet this could be a find oneliner

[Arndt]

I'm new to awk so I'll have to work on it a bit but:



#!/bin/bash
ls -lR somedir > ./somefilename
gawk somegawkfile.awk -f somefilename > ./outputfilelist


That should work but I'll have to get back with the somegawkfile.awk part!

Barrie

Edit: After some searching your list can be narrowed a bit! Click here! (http://ubuntuforums.org/showthread.php?t=688615)

There is some good stuff in that thread, but for the purpose of narrowing down a search, rather than suggesting what file names to create yourself, the only thing you can exclude is the forward slash '/'.

And it could be just as well that you don't exclude it either. Unix will never create such a file, but a foreign file system daemon might (that is a bug, of course). I remember this happening once, but I don't remember the details.

[mo.reina]

ls | grep -F '*'
ls | grep -F '"'
ls | grep -F '['
.......
.......
.......

[ibuclaw]

ls | grep -F '*'
ls | grep -F '"'
ls | grep -F '['
.......
.......
.......



grep -lR '[]*.":;=,|/\[]'

[stylishpants]

This one liner does it:

ruby -rfind -e 'chars=%q[*."/\\[]:;|=,].split(//); Find.find(".") { |f| puts f if chars.any?{|char| File.basename(f).include?(char)} }'

Here's the same code formatted and commented for readability:

#!/usr/bin/ruby -w
require 'find'

# Make an array of chars to search for
chars=%q[*."/\\[]:;|=,].split(//);

# Find all files/dirs under the current dir
Find.find(".") { |f|

# Print if the basename contains any target chars
puts f if chars.any?{|char| File.basename(f).include?(char)}
}

[mo.reina]

grep -lR '[]*.":;=,|/\[]'

gets my vote :D