Marvin666

December 5th, 2009, 07:47 PM

I'm taking algebra 1, but cant figure out this problem. I need to solve for x in the following:

(16/9*X)^2+x^2=299.29

(16/9*X)^2+x^2=299.29

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Marvin666

December 5th, 2009, 07:47 PM

I'm taking algebra 1, but cant figure out this problem. I need to solve for x in the following:

(16/9*X)^2+x^2=299.29

(16/9*X)^2+x^2=299.29

soni1770

December 5th, 2009, 07:54 PM

hey, don't post your homework.....:popcorn:

x = 8.491

x = 8.491

underquark

December 5th, 2009, 08:02 PM

or -8.491

Tmi

December 5th, 2009, 08:09 PM

I'm taking algebra 1, but cant figure out this problem. I need to solve for x in the following:

(16/9*X)^2+x^2=299.29

First use that (ab)^2 = a^2 * b^2

(16/9 * x)^2 is thus (16/9)^2 * x^2. After this you can solve for x

(16/9*X)^2+x^2=299.29 <-> (16/9)^2*x^2 + x^2 = 299.29 <-> x^2 * ((16/9)^2+1)=299.29 <-> x^2 = 299.29 / ((16/9)^2+1) <-> x = +- sqrt(299.29 / ((16/9)^2+1))

(16/9*X)^2+x^2=299.29

First use that (ab)^2 = a^2 * b^2

(16/9 * x)^2 is thus (16/9)^2 * x^2. After this you can solve for x

(16/9*X)^2+x^2=299.29 <-> (16/9)^2*x^2 + x^2 = 299.29 <-> x^2 * ((16/9)^2+1)=299.29 <-> x^2 = 299.29 / ((16/9)^2+1) <-> x = +- sqrt(299.29 / ((16/9)^2+1))

Marvin666

December 5th, 2009, 08:18 PM

Thanks, and I only do homework during study hall. I was figuring out a screens dimensions from it's diagonal and aspect ratio.

17.3" 16:9 = 15.095..." x 8.491"

17.3" 16:9 = 15.095..." x 8.491"

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