AWK... printing last record (NOTE: Record, not Field)

[nsa_767]

Hi there,

I'm very new to programming/scripting and I've been playing around with AWK... I would like some pointers as to how I would get AWK to print last record in a file... I've tried
basing my work on this example:


# print the first five input lines of a file, bit like head
FNR == 1, FNR == 5 { print $0 }

I attempted setting the FNR to NR-1 and NR, ie
FNR == (NR-1), FNR == NR { print $0 }, but it doesn't work.

Maybe my direct approach is too simplistic? Was wondering, should I maybe use a loop of some sort?

Before anyone asks, I have googled for this, but I didn't find anything.

BTW: If PERL can do this then I'm open to suggestions as to use it.

[kabus]

awk 'END{print}' filename

[nsa_767]

It works!! Cool, thanks man! I would never have thought it was that simple! Thanks again!