Cut chars from the end of string to the dilimeter char?

[PryGuy]

Good day, everyone!

The question is: I have a variable, it's an IP address. Say it's '192.168.0.1'. I want to cut characters counting backwards from the end of the string up to the '.' char. Is it possible to do it in pure bash?

I can't just cut a fixed number of characters, 'cause the length of the IP address can be different, eg. '192.168.0.1' and '10.215.215.10'.

Thank you in advance!

UPDATE! I have found the answer!!!

echo "192.168.0.1" | cut -d "." -f 1-3

[DaithiF]

Hi, you can do this directly in bash too, using a string replacement operator. saves you spawning a new process.


myvar=192.168.0.1
result=${myvar%.*}
echo $result
192.168.0