java methods.......

[abhilashm86]

can i have same method names in java?
i tried but there was errors, so i passes differnt datatypes, then it worked fine......

import java.util.Random;

public class samemehod {
void prt(String s) {
System.out.println(s);

}

int ret(int i) {
Random ran=new Random();
return i+ran.nextInt()%10;
}

double ret(double d) {
Random ran =new Random ();
return ran.nextDouble()%10+d;
}
public static void main(String[] args) {
samemehod s=new samemehod();
s.prt("int s="+s.ret(10));
s.prt("doube d="+s.ret(10.5));
}
}


as u see there is function
void prt(String s) {
System.out.println(s);

}
for this function if i pass like

s.prt(+10); or s.prt(10) it wont work
but it works if i write,

s.prt("int d="+10);

can i convert int to string before display or above method is correct?
how to keep same method name in above case, without passing any parameters?

[slavik]

for automatic conversion


s.prt(""+10);


or the proper OO approach



s.prt(new String(10));

[abhilashm86]

for automatic conversion
or the proper OO approach



s.prt(new String(10));


using this gives an error, compiler says
the constructor String(int) is undefined, why is this error?

[shadylookin]

can i have same method names in java?
i tried but there was errors, so i passes differnt datatypes, then it worked fine......


yes it's called method overloading. The name can be the same, but the parameters have to be different.



as u see there is function
void prt(String s) {
System.out.println(s);

}
for this function if i pass like

s.prt(+10); or s.prt(10) it wont work
but it works if i write,

s.prt("int d="+10);

can i convert int to string before display or above method is correct?
how to keep same method name in above case, without passing any parameters?

prt requires a string. 10 is not a string and +10 is not a string. To make it a string you have to have quotes like slavik has posted.

[Drone022]

Quote:
Originally Posted by slavik View Post
for automatic conversion
or the proper OO approach

Code:

s.prt(new String(10));

using this gives an error, compiler says
Code:

the constructor String(int) is undefined

, why is this error?

String(int) isn't a valid constructor so you would have to do

s.prt(new String("10"));

or maybe use a 'toString()' method


Integer int1 = new Integer(10);
s.prt(int1.toString());

Pretty sure an Integer is different from an int by the way.

[dribeas]

There is another way of implementing the conversion to String without the cost of concatenation ( ""+value, this implies creating an empty String object, and then creating a second String object with the number concatenated ) or creating an Integer you do not need ( new Integer(value).toString ):



int value = 10;
String str = Integer.toString( value );