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pauelmaco
August 18th, 2009, 12:07 PM
Hello

I'm learning a bit of python, and to learn I'm doing a very simple programa that does some operations. But I get an error when I'm trying to use the "factorial" function. Here is the code:

#
#This is a very simple program
#

bloca = 1

def factorial(a):
if a == 0:
return 1
else:
return a * factorial(a-1)

a = 0

tria = 0

ajuda = 1

suma = 2
sumaajuda = 200

resta = 3
restaajuda = 300

factorial = 4
factorialajuda = 400

#Start information

print "Simple program, version 0.01"
print "To get help, type'ajuda'"

while bloca == 1:

print " "

#Now the "promp" appears

tria = input("#>>> ")

if tria == 1:
print "This only can do some simple operations"
print "Possible commands are:"
print " "
print " suma"," factorial"
print " resta"
print " "
print "To get help, put 'ajuda' next the command"
print " "
print " "

if tria == 2:
print " "
a = input("To this: ")
print ab, "+", a, "=", ab +a
if tria == 200:
print " "
print "This command is to add numbers"

if tria == 3:
print " "
num1 = input("Treu aixo: ")
num2 = input("A aixo: ")
print num2, "-", num1, "=", num2 -num1
if tria == 300:
print " "
print "This command is to ...."

if tria == 4:
print " "
a = input("Put a number: ")

print factorial(a)

And I get an error like this:

#>>> factorial

Put a number: 5
Traceback (most recent call last):
File "interpret.py", line 84, in <module>
print factorial(a)
TypeError: 'int' object is not callable

Pleas, help me!!

Thanks

Arndt
August 18th, 2009, 12:40 PM
Hello

I'm learning a bit of python, and to learn I'm doing a very simple programa that does some operations. But I get an error when I'm trying to use the "factorial" function. Here is the code:

And I get an error like this:

Pleas, help me!!

Thanks

(If you had put the code inside CODE tags, not QUOTE tags, the quoting would work better here, and it would have been correctly indented, too.)

I think you define 'factorial' first as a function, but then override it by the assignment factorial=4. From that point on, it's an integer, and the function is gone.

pauelmaco
August 18th, 2009, 01:56 PM
(If you had put the code inside CODE tags, not QUOTE tags, the quoting would work better here, and it would have been correctly indented, too.)

I think you define 'factorial' first as a function, but then override it by the assignment factorial=4. From that point on, it's an integer, and the function is gone.

THANK YOU VERY MUCH. I now understand the problem!! :P:P:P