Very basic BASH problem

[ml_fan]

I have looked all over the place and tried a lot of different things but I am unable to get this to work

#!/bin/bash

position="a"

if["$position"=="a"];then
echo "great job"
fi


error message as follows:
./bash_sample.sh: line 5: syntax error near unexpected token `then'
./bash_sample.sh: line 5: `if[$position=="a"];then'

[x22]

#!/bin/bash

position=a

if [ $position = a ];then
echo "great job"
fi


*note spaces:-)

[ghostdog74]

use awk


awk 'BEGIN{
position="a"
if ( position == "a"){
print "ok"
}
}'

you don't have to worry about "=" being a valid equality sign when == is actually what you need.

[k2t0f12d]

I have looked all over the place and tried a lot of different things but I am unable to get this to work

#!/bin/bash

position="a"

if["$position"=="a"];then
echo "great job"
fi


error message as follows:
./bash_sample.sh: line 5: syntax error near unexpected token `then'
./bash_sample.sh: line 5: `if[$position=="a"];then'


package="a"
test "$package" -eq "a" && printf "Great job!"

[Habbit]

package="a"
test "$package" -eq "a" && printf "Great job!"

package="a"
test "x$package" -eq "xa" && printf "Great job!"
So that `test` won't die with "another argument expected" when $package is empty.

[k2t0f12d]

package="a"
test "x$package" -eq "xa" && printf "Great job!"
So that `test` won't die with "another argument expected" when $package is empty.


package="a"
test "$package" == "a" && printf "great job"

no, but I had the wrong operator there. try that

[ml_fan]

#!/bin/bash

position=a

if [ $position = a ];then
echo "great job"
fi


*note spaces:-)

Thank you.