How do You Compare Two Strings With Wildcards in Bash?

[Penguin Guy]

if [ "foobar" == *"bar" ]; then # Won't work because you need double brackets '[[...]]'
if [[ "foobar" == "*bar" ]]; then # Will not work because * is inside quotes
if [[ "foobar" == *"bar" ]]; then # Will work


Thanks to everyone who helped!

[akvino]

I am not sure if this is what you're looking for but if I were you I would set a variable to take the input or if you want

'$*' will give you the entire input argument.

[Martin Witte]

It has to do with quotation, see this link (http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_03_03.html)

martin@pc ~
$ if [[ "abc: GPG encrypted data" = *': GPG encrypted data' ]]; then echo Match
; fi
Match

[Penguin Guy]

Thank you! I just needed to put the '*' outside the quotation marks and use double square-brackets.

[Penguin Guy]

Here is the correct code:

#!/bin/bash
# Compare Test

if [[ "abc: GPG encrypted data" = *": GPG encrypted data" ]]; then
echo "Match!"
exit 0
else echo "No match."
fi

exit 1

[ghostdog74]

you can also use case/esac

[Penguin Guy]

Unless I am actually comparing multiple items, I think I'll stick with if for now, thanks anyawy!