Character count (python)

[ratmandall]

OK I sort of figured out how to do what I wanted, sort of as in I need to do other things with the string to actually make what I originally wanted but I'll do that by myself.

#!/bin/python
f = raw_input("blabla: ")
s = "guumom"#Wtf
print s
aa=s.rfind(f)
if aa >= 2:
    a = s.replace(f, "2" )#<<Would be 2 if "u" was entered, Meant to be how many times character specified appears, variable (aa) doesn't work??
    print a
else:
    print "naww" 

[Greyed]

Er, ok, since you put up code, here is what I was alluding to in my first reply. A for loop, a placeholder and a counter...

def letters(word=''):      
    count = 1 # Counter   
    prev = '' # Placeholder
    for c in word: # For loop
        if c != prev:
            if prev: # Prevents printing the empty prev.
                print prev, count
            count = 1
            prev = c
        elif c == prev:
            count = count + 1
    else: # needed to print out the final letter's count
        print c, count

while 1:
    letters(raw_input(': ')) 

Results in the following.

{grey@igbuntu:~} python foo.py
: mississippi                 
m 1                           
i 1                           
s 2                           
i 1                           
s 2                           
i 1                           
p 2                           
i 1                           
: ragoo                       
r 1                           
a 1                           
g 1                           
o 2                           
: Gooooooooooooooaaaaaaaallllll!!
G 1                              
o 14                             
a 8                              
l 6                              
! 2

Since that accurately counts all letters it is simply a matter of adjusting the exact display logic with a few ifs. Or, if you're getting really fancy, throwing it all into a dict of lists and extracting the information from that dict as needed.

[ratmandall]

Er, ok, since you put up code, here is what I was alluding to in my first reply. A for loop, a placeholder and a counter...

def letters(word=''):      
    count = 1 # Counter   
    prev = '' # Placeholder
    for c in word: # For loop
        if c != prev:
            if prev: # Prevents printing the empty prev.
                print prev, count
            count = 1
            prev = c
        elif c == prev:
            count = count + 1
    else: # needed to print out the final letter's count
        print c, count

while 1:
    letters(raw_input(': ')) 

Results in the following.

{grey@igbuntu:~} python foo.py
: mississippi                 
m 1                           
i 1                           
s 2                           
i 1                           
s 2                           
i 1                           
p 2                           
i 1                           
: ragoo                       
r 1                           
a 1                           
g 1                           
o 2                           
: Gooooooooooooooaaaaaaaallllll!!
G 1                              
o 14                             
a 8                              
l 6                              
! 2

Since that accurately counts all letters it is simply a matter of adjusting the exact display logic with a few ifs. Or, if you're getting really fancy, throwing it all into a dict of lists and extracting the information from that dict as needed.

Actually yea that's sort of what I wanted I just realised my code is wrong because I didn't fully test it, thanks