[Beginner] Programming Challenge: 1

[CLomax]

#include <stdio.h>

int main()
{
      int b, i;

   b = 99;
   i = 98;

 for(b=99;b>1;b--)
 {
   printf("%d bottles of beer on the wall %d bottles of beer.\nTake one down and pass it around, %d bottles of beer on the wall.\n\n",b,b,i--);
 }
 return(0);
} 

Here's my C code... not really that good but it does the job and it weighs in at about 256 bytes.

[pp.]

it does the job

Have you looked at the last two "verses" your program has to produce, i.e. at #bottles=1 and #bottles=0?

[CLomax]

Have you looked at the last two "verses" your program has to produce, i.e. at #bottles=1 and #bottles=0?

Woops
And I thought I manage to reduce it further than others did. I'll look into that. Thanks.

[bgs100]

#!/usr/bin/python
beer=99
#normal stuff, 99 to 3
while beer > 2: 
    print "%i bottles of beer on the wall, %i bottles of beer, take one down, pass it around, %i bottles of beer on the wall\n" % (beer,beer,beer-1)
    beer=beer-1
#Ending with correct grammar
print "2 bottles of beer on the wall, 2 bottles of beer.\nTake one down and pass it around, 1 bottle of beer on the wall.\n" 
print "1 bottle of beer on the wall, 1 bottle of beer.\nTake one down and pass it around, no more bottles of beer on the wall.\n"
print "No more bottles of beer on the wall, no more bottles of beer.  Go to the store and buy some more, 99 bottles of beer on the wall." 

I am a python noobie. Edited beforehand for correct grammar on 1 and 2

[eightmillion]

Here's my python one liner:

python -c 'bo,be,ta,wa,no="bottle","of beer","Take one down and pass it around","on the wall",range(99,0,-1); print "".join([ "%s %s%s %s %s,\n%s %s%s %s.\n%s, %s %s%s %s %s.\n\n" % (num,bo,["s",""][num==1],be,wa,num,bo,["s",""][num==1],be,ta,[num-1,"no more"][num-1==0],bo,["s",""][num-1==1],be,wa) for num in no ] + ["No more %ss %s %s, no more %ss %s.  Go to the store and buy some more, 99 %ss %s %s." % (bo,be,wa,bo,be,bo,be,wa)] )'

Edit: Also, a version for bash:

bo="bottle";be="of beer";ta="Take one down and pass it around";wa="on the wall";i=99;while [ "$i" != 0 ]; do printf "$i $bo`[ $i != 1 ] && echo s` $be $wa,\n$i $bo`[ $i != 1 ] && echo s` $be.\n$ta, `[ $((i-1)) != 0 ] && echo $((i-1)) || echo "no more"` $bo`[ $i != 2 ] && echo s` $be.\n\n"  ;i=$((i-1));done;  printf "No more ${bo}s $be $wa,\nno more ${bo}s $be.\nGo to the store and buy some more, 99 ${bo}s $be $wa.\n"

[baizon]

Java:

public class NinetyNineBottles {

	private static void bottlesCounter(int bottles) {
		for (; bottles > 0; bottles--) {
			if (bottles == 1) {
				System.out.println(bottles + " bottle of beer on the wall, " + bottles + " bottle of beer.");
				System.out.println("Take one down and pass it around, no more bottles of beer on the wall.");
			} else {
				System.out.println(bottles + " bottles of beer on the wall, " + bottles + " bottles of beer.");
				System.out.println("Take one down and pass it around, " + (bottles - 1) + " bottles of beer on the wall.");
			}
		}
	}
	
	public static void main(String[] args) {
		bottlesCounter(99);
	}
}

[xfice]

Here is my answer in the first problem. any comments? I used C.

#include<stdio.h>

int qty;

main(){
for(qty=99;qty!=1;qty--){
printf("%d bottles of beer on the wall, %d bottles of beer.\n", qty,qty);
printf("Take one down and pass it around, %d bottles of beer on the wall.\n", qty-1);
}
if(qty=1){
printf("%d bottle of beer on the wall, %d bottle of beer.\n", qty, qty);
printf("Take one down and pass it around, no more bottles of beer on the wall.\n");

printf("No more bottles of beer on the wall, no more bottles of beer. \nGo to the store and buy some more, 99 bottles of beer on the wall.\n");

}
}