[SOLVED] Python: search file like grep

[dbbolton]

I want to do something like grep with python. I have a file, and I want to search it for a string, and print the line containing that string. Is this possible, and if so, how can I do it?

[ghostdog74]

I want to do something like grep with python. I have a file, and I want to search it for a string, and print the line containing that string. Is this possible, and if so, how can I do it?

for line in open("file"):
 if "search_string" in line:
   print line

always read up the documentation and tutorials if you don't know anything.

[dbbolton]

for line in open("file"):
 if "search_string" in line:
   print line

always read up the documentation and tutorials if you don't know anything.

Thanks. I have been reading the docs and a few tutorials, but I got stuck on this one.

Also, do you know whether it's possible to print only the first occurrence of the search string?

[WW]

Also, do you know whether it's possible to print only the first occurrence of the search string?

Just put a break statement after the print statement.

[dbbolton]

Thanks

[helpdeskdan]

Another thanks!

[jdb91]

So I'm doing

for line in open("text.txt"):
 if "ref" in line:
  print line

And getting back

ref= 1

(For example)

All I want displayed is the "1"

How do I format the output of print line to print just the second part (in bash it would be awk {print $2})

[ghostdog74]

you just need to split .

print line.split("=")[-1]

i thought you have been reading the docs? split() is very basic for Python string processing.