Urgent!!!!
please help me with this program.. we are trying to create a program to generate timetable..
the following segment of the program is showing me an error:
General Protection Exception Processor Fault
here is the code segment...
Code:#include<iostream.h> #include<fstream.h> #include<stdlib.h> #include<stdio.h> #include<string.h> #include<math.h> #include<ctype.h> #include<iomanip.h> #include<process.h> #include<time.h> class linkobj { public: char name[25]; int cls,sec; }; class Subject {public: char sname[10]; void stores() {cout<<"Enter name of subject : "; gets(sname); } class teacher {public: int nocls; char tname[25]; class pref {public: int cls; int sec; }preff[5]; class day {public: char dname[10]; class period {public: int clssoft; int section; }p[8]; }d[6]; }t[7]; void write(); void show(); }*s=new Subject[3]; class Class {public: int cname; class section { public: char secname[10]; class day {public: char dname[10]; class period {public: char nameoftheteachertakingclass[25]; ///when outputting setw }p[8]; }d[6]; }sec[4]; void write1(); void storedataofstudent(); } cls[5]; int i,j,k; /*void Class:: storedataofstudent() { for(i=0;i<5;++i) {cls[i].cname=(i+1); {for(j=0;j<4;++j) { if(j==0) strcpy(cls[i].sec[j].secname,"a"); else if(j==1) strcpy(cls[i].sec[j].secname,"b"); else if(j==2) strcpy(cls[i].sec[j].secname,"c"); else if(j==3) strcpy(cls[i].sec[j].secname,"d"); for(k=0;k<6;++k) { if(k==0) strcpy(cls[i].sec[j].d[k].dname,"MONDAY"); else if(k==1) strcpy(cls[i].sec[j].d[k].dname,"TUEDAY"); else if(k==2) strcpy(cls[i].sec[j].d[k].dname,"WEDNESDAY"); else if(k==3) strcpy(cls[i].sec[j].d[k].dname,"THURSDAY"); else if(k==4) strcpy(cls[i].sec[j].d[k].dname,"FRIDAY"); else if(k==5) strcpy(cls[i].sec[j].d[k].dname,"SATURDAY"); } } } } } */ struct teacher {int randnum,ab; int seedval,clss,secc,k,l,sub,tecr,f; }s1; struct k { struct l{ char c[5][25]; }b[4]; }a[5]; void selectteacher() { //time_t t; //s1.seedval=time(&t); srand(time(NULL)); //char x[5][4][5][25]; // for(s1.clss=0;s1.clss<5;s1.clss++) { for(s1.secc=0;s1.secc<4;s1.secc++) { int f=0; //this name and select one from this using random and assign the values to the major classes of teacher and student. while(f!=5)//////////////////// exit from the loop { for(s1.sub=0;s1.sub<3;++s1.sub) { for(s1.tecr=0;s1.tecr<1;s1.tecr++)///to search the whole teacher's class and select the teachers who have selected this class and this section. {for(s1.k=0;s1.k<5;s1.k++)//the preferred class she needs there are 5 of them if((s[s1.sub].t[s1.tecr].preff[s1.k].cls==s1.clss)&&(s[s1.sub].t[s1.tecr].preff[s1.k].sec==s1.secc)) { //this teacher will have only once select this class if she actually wants it { strcpy(a[s1.clss].b[s1.secc].c[f],s[s1.sub].t[s1.tecr].tname); ///////////////////////////// TERROR! f++; if(f==5) break; } } } } } } } for(s1.clss=0;s1.clss<5;s1.clss++) { for(s1.secc=0;s1.secc<4;s1.secc++) { for(s1.k=0;s1.k<6;s1.k++)//day {for(s1.l=0;s1.l<8;s1.l++) //period { s1.ab=(rand()%5)+0;// The random is generated between 0 to 5 and is used to dereference into the pointer's index // and five such teachers' names are stored into the teacher's name of the class teacher. ///condition so that not more than 2 continuous random nos are the same. strcpy( cls[s1.clss].sec[s1.secc].d[s1.k].p[s1.l].nameoftheteachertakingclass,a[s1.clss].b[s1.secc].c[s1.ab]);//////////////////////////// //s[clss].t[secc].d[k].p[l].cls=clss; //s[clss].t[secc].d[k].p[l].sec=secc; } } } } } void main() { selectteacher(); }
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Originally Posted by trent.josephsen
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