Remove #

[fadder]

Here's a perl solution (don't know how to keep indents, sorry..):

while(<>){ # Loops over standard input
if (/^# .* foo .*/x) {
s/foo/bar/;
s/^#//;
}
print;
}

[christhemonkey]

Ok, ignore the removing of #'s sorted that with another function.

Just need to know how to replace foo with bar on a random line.

import fileinput
for line in fileinput.FileInput("file.name", inplace=1): #do inplace editing..
if line[0] == '#' and "foo" in line:
line = line.replace("foo","bar")
print line

This sounds like what i want, but i want to save this change to file which im not sure this does...

[pmasiar]

Google is your friend:

http://pydoc.org/2.4.1/fileinput.html

Optional in-place filtering: if the keyword argument inplace=1 is passed to input() or to the FileInput constructor, the file is moved to a backup file and standard output is directed to the input file. This makes it possible to write a filter that rewrites its input file in place. If the keyword argument backup=".<some extension>" is also given, it specifies the extension for the backup file, and the backup file remains around; by default, the extension is ".bak" and it is deleted when the output file is closed.

This is why I love python - often used functionality is neatly packed, ready to be used.

Thanks ghostdog74, I learned another neat library function.

[ghostdog74]

Thanks ghostdog74, I learned another neat library function.

No problem