how to export first string in command

[sccuser]

Hi, please help me in the following matter, that I would like to export the first string of certain line of command, for example:

root@ubuntu:~# who
root pts/0 2012-12-25 17:18 (ubuntu.domain.name.com)
firstname.lastname tty7 2012-12-25 16:55

The thing that I need is ONLY "firstname.lastname" information, not including the rest.
Much appreciated!
Have a good day guys.

[steeldriver]

a couple of ideas

$ echo "firstname.lastname tty7 2012-12-25 16:55" | awk '{print $1}'
firstname.lastname
$
$ echo "firstname.lastname tty7 2012-12-25 16:55" | cut -d' ' -f1
firstname.lastname
$

[rnerwein]

Hi, please help me in the following matter, that I would like to export the first string of certain line of command, for example:

root@ubuntu:~# who
root pts/0 2012-12-25 17:18 (ubuntu.domain.name.com)
firstname.lastname tty7 2012-12-25 16:55

The thing that I need is ONLY "firstname.lastname" information, not including the rest.
Much appreciated!
Have a good day guys.

hi
who | awk '{print $1}'

[sccuser]

Perfect!
Thanks so much steeldriver & rnerwein.

Just one more question please.
For the out put

firstname.lastname tty7 2012-12-25 16:55

what's the solution if I need

tty7

or

2012-12-25

or

16:55

Edit: yep I've got it, please forget. Thanks guys!

[rnerwein]

Perfect!
Thanks so much steeldriver & rnerwein.

Just one more question please.
For the out put
what's the solution if I need
or
or


Edit: yep I've got it, please forget. Thanks guys!

ok
$0 is the whole string (line)
$1 is the first field delimited by " " space ....
$2 is the second field
......
so if you want to have only the time: who | awk ' { print $4 }'
and if you want to get the tty : who | awk '/tty/ { print $2}'
awk is a powerful tool try to learn it.
cheers