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Thread: Counting inside a for loop

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  1. #1
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    Counting inside a for loop

    So I'm doing an independent study on python 3 in school right now, and I was working on this problem: http://interactivepython.org/coursel...s/montepi.html

    The problem is, I can't figure out how to have my code count the number of red "darts" (the darts that hit the target), since everything I've tried always gives me a 0. This is what I currently have:
    Code:
    import turtle
    import math
    import random
    
    wn = turtle.Screen()
    wn.setworldcoordinates(-1,-1,1,1)
    
    jim = turtle.Turtle()
    
    def dartboard (someturtle):
        someturtle.speed(0)
        drawCircle(someturtle)
        drawSquare(someturtle) #create square board around circle
    
    def drawCircle(someturtle):
        someturtle.up()
        someturtle.goto(0, -1)
        someturtle.down()
        someturtle.circle(1, 360, 1000)
    def drawSquare(someturtle):
        someturtle.up()
        someturtle.goto(1, -1)
        someturtle.down()
        for square in range(4):
            someturtle.lt(90)
            someturtle.fd(2)
            
    def colorDart(someturtle):
        if someturtle.distance(0, 0) <= 1:
            someturtle.color('red')
        else:
            someturtle.color('blue')
    
    dartboard(jim)
    jim.up()
    
    numdarts = 10
    insideCount = 0
    for i in range(numdarts):
        randx = random.uniform(-1, 1)
        randy = random.uniform(-1, 1)
        jim.goto(randx, randy)
        colorDart(jim)
        jim.stamp()
        if jim.color() == 'red':
            insideCount += 1
    print(insideCount)
    
    wn.exitonclick()
    As you may have noticed, I'm trying to increment insideCount every time turtle jim is red, but for some reason this doesn't work.
    What am I doing wrong?

  2. #2
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    Re: Counting inside a for loop

    Well, I solved it by changing
    Code:
        if jim.color() == 'red':
            insideCount += 1
    to
    Code:
        if jim.distance(0, 0) <= 1:
            insideCount += 1
    However, I'm still curious: is there a way to increment using the color as the deciding factor, like I did in my original post?

  3. #3
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    Re: Counting inside a for loop

    what do you get from jim.color()? i see that color() is a method setting the color, but i am not convinced it returns what you think it returns.
    add some print statement to make things clear eg print( jim.color() )
    if your question is answered, mark the thread as [SOLVED]. Thx.
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  4. #4
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    Re: Counting inside a for loop

    Quote Originally Posted by Vaphell View Post
    what do you get from jim.color()? i see that color() is a method setting the color, but i am not convinced it returns what you think it returns.
    add some print statement to make things clear eg print( jim.color() )
    Inserting a "print(jim.color())" right after jim.stamp() returned:
    Code:
    ('blue', 'blue')
    ('red', 'red')
    ('red', 'red')
    ('red', 'red')
    ('red', 'red')
    ('red', 'red')
    ('red', 'red')
    ('blue', 'blue')
    ('red', 'red')
    ('red', 'red')
    I changed my code to
    Code:
    if jim.color() == ('red', 'red'):
    and that worked. And now that I think about it, that makes sense, since the .color() method sets both the pen color and the fill color, which would explain the two values returned each time print(jim.color()) was executed. So if I wanted to do what I had originally planned, I would have to use either .pencolor() or .fillcolor(), since they only hold a single value.

    Thanks for the help! This has really helped me learn more about how python works.

  5. #5
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    Re: Counting inside a for loop

    Quote Originally Posted by DaimyoKirby View Post
    Well, I solved it by changing
    Code:
        if jim.color() == 'red':
            insideCount += 1
    to
    Code:
        if jim.distance(0, 0) <= 1:
            insideCount += 1
    However, I'm still curious: is there a way to increment using the color as the deciding factor, like I did in my original post?
    You draw a circle, not a full disc, so inside your circle you still have the original color. You'll see red only if you are exactly on the circle.

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