bash capture output between two ""

[Drenriza]

Hi all.

I have some output as follows

SYSTEM    	"2M Hotel"

How can i capture the text between the two "" so the only output i get is 2M Hotel ?

Thanks on advance.
Kind regards.

[WasMeHere]

I think it works if you pipe your output through

sed s/.*\ \"//|sed s/\"$//

Have fun
Olle

[Lars Noodén]

Another way is to pipe it through awk while setting the Output Field Separator to a double quote (")

yourscript | awk -F '"' '{print $2}'

-F sets the field separator, $2 is the second column

Obviously there are limitations to this method.

[tors]

Another sed:

#> echo 'SYSTEM    "2M Hotel"' | sed "s/.*\"\(.*\)\"/\1/g"
2M Hotel
#>

[dargaud]

Another sed, which avoid parentheses:

yourscript | sed -e 's/[^"]*"//' -e 's/".*//'

[Drenriza]

Thanks for all the suggestions guys. Wish i knew what all those characters in the sed commands ment. But it looks a bit exhausting to be honest.

[ofnuts]

Thanks for all the suggestions guys. Wish i knew what all those characters in the sed commands ment. But it looks a bit exhausting to be honest.

These are "regular expressions" and any programmer worth his salt should know about them.

http://xkcd.com/208/

[Lars Noodén]

Thanks for all the suggestions guys. Wish i knew what all those characters in the sed commands ment. But it looks a bit exhausting to be honest.

They are not just for programmers, they're essential also to system administration.

There are lots of sources of material on regular expressions. For sed you can start here:

http://www.gnu.org/software/sed/manu...pressions.html

http://www.faqs.org/docs/abs/HTML/regexp.html