Finding file size. How could I exclude directories?

**Zombir** · January 18th, 2011

Hi all,

I'm trying to write a bash script in Ubuntu and I need the file sizes in a specified directory. I searched for it in the net but all the solutions suggested showed sizes of files and directories. I want the sizes of files only, in my script. How can I find only the file sizes? Please help. (Hope this is relevant to this forum)

Thanks in advance.

**Vaphell** · January 18th, 2011

Code:

ls -la | awk '/^-/ { print $8, $5 }'

or

Code:

find . -maxdepth 1 -type f -exec stat -c%n\ %s '{}' \;

**bleutyler** · January 18th, 2011

Code:

find . -type f -maxdepth 1 -exec ls -l {} \;

However, since the ls -l command is being run on each file independantly, the columns will not line up.

you can always grep your ls -l results.

Code:

ls -l | grep -vE "^d"

This will have columns lined up.

**Zombir** · January 18th, 2011

Thanks both of you. It seems an awful lot of symbols to me. Sorry I'm just a starter. Anyway, I won't exhaust you asking for explanations. I'll google and see if I could decipher them. Thank you once again.

**Cheezespread** · January 18th, 2011

I just had a quick question on the maxdepth in find. What would "-maxdepth 1" do ? .Does it consider only the files in the current directory and ignore any directories below that ?

I looked into the manpages after I noticed it in your responces and was a bit confused.