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Hello everybody with powerpc's,
I'm looking to find a way of identifying which ram slots are used. Unfortunately I have 3 gigs worth of DIMMs installed but only 1.5GB of memory show up as recognized by /proc/MemTotal or in System Monitor.
I found how to do this with intel/amd architecture but it requires the BIOS in the machines to be read with dmidecode. As this is a powermac G5 dual 2.5ghz dmidecode isn't even in the powerpc repositories.
How do you all find which ram slots are being used?
try this you may have to scroll and look for it
dmidecode -q | less
it will output a lot of info but your looking for something like this
Quote:
Memory Device
Total Width: 64 bits
Data Width: 64 bits
Size: 2048 MB
Form Factor: DIMM
Set: None
Locator: DIMM_3
Bank Locator: Not Specified
Type: DDR
Type Detail: Synchronous
Speed: 800 MHz
Manufacturer: 0000000000000000
Serial Number: 00000000
Asset Tag: 000000
Part Number: 2G U64CP8-S6
Dude, read the second half of my post. dmidecode doesn't work with PowerPC
I need advice about OpenFirmware aka OpenBoot. Anybody out there a Solaris admin? or a Old time X-Serve guru? Or a IBM POWER sysadmin?
Any Unix Guru's out there that know about Firmware in general? Coreboot folks?
ususally from OF you are able to see the installed ram:
Anyway remember to reset NVRAM/PRAM everytime you modify your hw configuration.Code:> dev /memory@0
> .properties
Wow, thank you BarbaGNU. I needed a solid answer like that.
May I ask you how you found my thread? As you can see I tried to put a lot of keywords in my second post so that it would be more search friendly.
i'm glade you solved.
About tags... no, i don't. I simply/seldom read this forum interested in ppc topics.
Hey BarbaGNU,
I have a follow up question.
After googling dev /memory@0 and .properties I found that you can set openfirmware to display base 10 instead of hexidecimal. But it doesn't in the memory's .properties.
Any suggestions?
Or should I just get out a scientific calculator and figure it out?
no idea, sorry.