Question to for in loop

[hovzio]

Hi, I've been learning about shell scripting and have been working on this the last few hours... :(
I'm new to shell scripts and this is my first bout with a for in loop.An example out of a book I'm working with:

for i in *
do
if [ -d "$i" ];then
echo "$i"
fi
done

I understand the concept of the example its just I wanted (for exp. purposes) to add another command (example ls -l) in there and I noticed it didn't work.Why is this and how can I make it happen?

for i in *
do
if [ -d "$i" ];then
echo "$i"
ls -l "$i" #doesn't work..
echo `ls -l "$i"` #dido, I know its far fetched
ls -l "$i" 1>&2 # nope
fi
done

How can I get the output of ls -l (or any command of that nature) to my screen. I know its a real simple answer...Any direction or help to any answer would be fully appreciated.

[Cypher]

I tried the following code in a file called 'foo' on my Kubuntu 8.04 and it worked fine.

for i in *
do
if [ -d "$i" ]; then
echo "$i"
ls -l $i
fi
done

I executed the command as

sh foo

[hovzio]

Thanks!!