Find a shell script's location within the script?

[maybeway36]

Is there a way from inside a shell script to find out where the script is located (which folder it is in?)

[chewearn]

pwd

[LaRoza]

pwd

That will print the working directory, not the scripts location.

[ghostdog74]

Is there a way from inside a shell script to find out where the script is located (which folder it is in?)
you can try $0
eg

#!/bin/bash
scriptpath=$0
case $scriptpath in
./*) echo `pwd` ;;
* ) dirname $scriptpath
esac

[stroyan]

Bash reports paths to the files it is running from in the BASH_SOURCE array.
You may want to use readlink to find the real path through symbolic links.

script_dir="$(dirname "$(readlink -f ${BASH_SOURCE[0]})")"

[bennit]

cd `dirname`; pwd

[mangup]

This one also works, though it's a bit lengthy:

# Function returns the full path to the current script.
# Example:
# tmp=`currentscriptpath`
# echo "path to current script is: "$tmp
currentscriptpath()
{
local fullpath=`echo "$(readlink -f $0)"`
local fullpath_length=`echo ${#fullpath}`
local scriptname="$(basename $0)"
local scriptname_length=`echo ${#scriptname}`
local result_length=`echo $fullpath_length - $scriptname_length - 1 | bc`
local result=`echo $fullpath | head -c $result_length`
echo $result
}