View Full Version : [SOLVED] C++ algorithm count_if

February 2nd, 2008, 08:56 PM
hi there;

I have decided to use the C++ standard libraries algorithms for the first time,
so the first problem i was going to solve with it was basically counting the number of "trues" in a vector of bools, simple enough, but its confusing me;

here is the code that i have:

int countTrues(const vector<bool>& vec)

return (int) count_if (vec.begin(), vec.end(), isTrue);


bool isTrue(bool val)
return val;

now with my good old C i could have written this in one line, so is there any way not to have to use an additional function? is there any way to use the algorithms to solve this problem in less number of lines?



February 2nd, 2008, 09:12 PM
Why not use plain std::count? std::count_if is best used for "fancy" predicates, which is clearly not your case.

February 2nd, 2008, 09:23 PM
hi there;

oh I didnt know about count, thanks, i looked it up, its exactly what i need;

this is the problem when you try to use something you havnt learned systematically :S



February 2nd, 2008, 09:24 PM
the c++ boost libraries have a lambda facility

but, i'm not gonna bother with lambdas in c++ .. here is how it looks in lisp tho:

(defun count-trues (sequence)
(count-if (lambda (val) val)

edit: i guess i kinda answered a different question; "how to splice the function definition 'into' the function call" -- that is how i read it :)

February 4th, 2008, 08:16 AM
#include <vector>
#include <algorithm>
#include <functional>

int main()
std::vector<bool> vec(3);
vec.at(0) = true;
vec.at(1) = false;
vec.at(2) = true;

std::count_if(vec.begin(), vec.end(), std::bind2nd(std::equal_to<bool>(), true));

February 4th, 2008, 12:33 PM
uljanow I really like your example. :)

Reminds me of one of my favourite sayings (roughly translated from french): "why make it simple when you could make it complicated?" ;)