Apache - ServerAlias exception

[StrangeWill]

So lets say I have two sites:
domain.com (www.domain.com)
www2.domain.com

I want all aliases to point to domain.com ex:
ServerAlias *.domain.com
which means www.domain.com -> domain.com, somesite.domain.com -> domain.com. Great.


Except, www2.domain.com -> domain.com.... www2.domain.com is another site, is there a way to use wildcard exceptions? Every other combination OTHER THAN www2.domain.com will go to domain.com?

I've started listing:

ServerAlias site1.domain.com
ServerAlias *.site1.domain.com
ServerAlias site2.domain.com
ServerAlias *.site2.domain.com
ServerAlias site3.domain.com
ServerAlias *.site3.domain.com
ServerAlias site4.domain.com
ServerAlias *.site4.domain.com


but this requires a restart every time a new site is added, and is going to become a mess very quickly.

Thanks. :)

[a9k3d]

You want to use <VirtualHost _default_> in your /etc/apache2/sites-available/default
and then use
<VirtualHost *>
ServerName www2.domain.com
...
for the www2 site
Make sure /etc/apache2/ports.conf has NameVirtualHost * in it.

ServerAlias is used for another name of the site it's configuring. Example:
ServerName www.fish.com
ServerAlias fish.com

[StrangeWill]

You want to use <VirtualHost _default_> in your /etc/apache2/sites-available/default
and then use
<VirtualHost *>
ServerName www2.domain.com
...
for the www2 site
Make sure /etc/apache2/ports.conf has NameVirtualHost * in it.

ServerAlias is used for another name of the site it's configuring. Example:
ServerName www.fish.com
ServerAlias fish.com


So I'm assuming I need www2.domain.com to come first as a virtual host, and then just use *.domain.com on the 2nd virtual host, correct?

I'm not 100% sure how this will work, plesk may throw up, but I'll investigate ASAP.

[ICEB3AR]

You could use:

#Default-Directory which is used, if the subdomain/domain is not found
DocumentRoot "/<path to your www.domain.de directory>"

#define your subdomain www2.domain.com
<VirtualHost *:80>
...
</VirtualHost>

THis should work.